810B - Summer sell-off - CodeForces Solution


greedy sortings *1300

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Python Code:

n, f = list(map(int, input().split()))
store = []

class day:
    def __init__(self, K_i, L_i):
        self.client = L_i
        self.products = K_i


for i in range(n):
    K_i, L_i = list(map(int, input().split()))
    store.append(day(K_i, L_i))

store = sorted(store, key=lambda x : min(2 * x.products, x.client) - min(x.products, x.client), reverse= True)
    

for i in range(f):
    store[i].products = store[i].products * 2

sum = 0
for i in store:
    if i.products > i.client:
        sum += i.client
    else:
        sum += i.products
print(sum)

C++ Code:

#include<iostream>
#include<vector>
#include<algorithm>
#include<map>
#include<cmath>
#include<set>
#include <numeric>
using namespace std;
const long double pi = 2 * acos(0.0);
#define all(v) ((v).begin()),((v).end())
#define sz(v) (int)(v.size())
#define p_b   push_back
#define fi    first
#define se    second
#define ma    make_pair
#define oo    1e8
typedef long long ll;
typedef vector< vector<int> >vv;
typedef vector<ll>vi;
typedef vector<bool> vb;
#include<stdio.h>
int x_ax[] = {0,0,1,-1,-1,-1,1,1},
y_ax[] = {1,-1,0,0,1,-1,1,-1};
bool valid(int r, int c, int n, int m) {
    return !(r < 0 || r >= n || c < 0 || c >= m);
}
int gcd(int a, int b) {
    if (!b)return a;
    return gcd(b, a % b);
}


int main() {
ll n,f,ans=0;cin>>n>>f;
vector<ll>p(n);
for(ll x=0,fr,sc;x<n;x++){cin>>fr>>sc;
ans+=min(fr,sc);
if(fr<sc&&(2*fr)<=sc)p[x]=(2*fr)-fr;
else if(fr<sc&&(2*fr)>sc)p[x]=sc-fr;
else p[x]=0;
}
sort(all(p),greater<ll >());
for(ll x=0;x<f;x++)ans+=p[x];
cout<<ans;
}


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